(x-5)^2=3x(x-+3)

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Solution for (x-5)^2=3x(x-+3) equation: 



(x-5)^2=3x(x-+3)

We move all terms to the left:

(x-5)^2-(3x(x-+3))=0

We add all the numbers together, and all the variables

(x-5)^2-(3x(+x))=0



We calculate terms in parentheses: -(3x(+x)), so:

3x(+x)

We multiply parentheses

3x^2

Back to the equation:

-(3x^2)



determiningTheFunctionDomain
-3x^2+(x-5)^2=0

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